Marion and Michael collect pencils and erasers. Michael has 80 more erasers than pencils. Michael has 4 times the number of pencils Marion has, and Marion has 40% more erasers than Michael. After Marion gives Michael all of her pencils and Michael gives Marion 60% of his erasers, Michael has 36 more pencils than erasers. Find the number of erasers Marion has at first.
Marion |
Michael |
Erasers |
Pencils |
Erasers |
Pencils |
5.6 u + 112 |
1 u |
4 u + 80 |
4 u |
+ 2.4 u + 48 |
- 1 u |
- 2.4 u - 48 |
+ 1 u |
8 u + 160 |
0 |
1.6 u + 32 |
5 u |
100% + 40% = 140%
140% x 4 u
=
140100 x 4 u
= 5.6 u
140% x 80
=
140100 x 80
= 112
60% x 4 u
=
60100 x 4 u
= 2.4 u
60% x 80
=
60100 x 80
= 48
If another 36 erasers are given to Michael, he will have equal number of erasers and pencils in the end.
5 u = 1.6 u + 32 + 36
5 u - 1.6 u = 68
3.4 u = 68
1 u = 68 ÷ 3.4 = 20
Number of erasers that Marion has at first
= 5.6 u + 112
= 5.6 x 20 + 112
= 112 + 112
= 224
Answer(s): 224