Tina and Cody collect cards and coins. Cody has 60 less cards than coins. Cody has 2 times the number of cards Tina has, and Tina has 20% more coins than Cody. After Tina gives Cody all of her cards and Cody gives Tina 60% of his coins, Cody has 9 less coins than cards. Find the number of coins Tina has at first.
| Tina |
Cody |
| Coins |
Cards |
Coins |
Cards |
| 2.4 u + 72 |
1 u |
2 u + 60 |
2 u |
| + 1.2 u + 36 |
- 1 u |
- 1.2 u - 36 |
+ 1 u |
| 3.6 u + 108 |
0 |
0.8 u + 24 |
3 u |
100%+ 20% = 120%
120% x 2 u
=
120100 x 2 u
= 2.4 u
120% x 60
=
120100 x 60
= 72
60% x 2 u
=
60100 x 2 u
= 1.2 u
60% x 60
=
60100 x 60
= 36
If another 9 coins are given to Cody, he will have equal number of coins and cards in the end.
3 u = 0.8 u + 24 + 9
3 u - 0.8 u = 33
2.2 u = 33
1 u = 33 ÷ 2.2 = 15
Number of coins that Tina has at first
= 2.4 u + 72
= 2.4 x 15 + 72
= 36 + 72
= 108
Answer(s): 108 
