Min and Julian collect cards and coins. Julian has 60 less cards than coins. Julian has 5 times the number of cards Min has, and Min has 30% more coins than Julian. After Min gives Julian all of her cards and Julian gives Min 70% of his coins, Julian has 72 less coins than cards. Find the number of coins Min has at first.

Min		Julian
Coins	Cards	Coins	Cards
6.5 u + 78	1 u	5 u + 60	5 u
+ 3.5 u + 42	- 1 u	- 3.5 u - 42	+ 1 u
10 u + 120	0	1.5 u + 18	6 u

100%+ 30% = 130% 

130% x 5 u
= ¹³⁰₁₀₀ x 5 u
= 6.5 u

130% x 60
= ¹³⁰₁₀₀ x 60
= 78 

70% x 5 u
= ⁷⁰₁₀₀ x 5 u
= 3.5 u  

70% x 60 
= ⁷⁰₁₀₀ x 60
= 42 

If another 72 coins are given to Julian, he will have equal number of coins and cards in the end.
6 u = 1.5 u + 18 + 72
6 u - 1.5 u = 90
4.5 u = 90

1 u = 90 ÷ 4.5 = 20

Number of coins that Min has at first
= 6.5 u + 78
= 6.5 x 20 + 78
= 130 + 78
= 208
 
Answer(s): 208