Jaslyn and Peter collect erasers and beads. Peter has 60 less erasers than beads. Peter has 2 times the number of erasers Jaslyn has, and Jaslyn has 40% more beads than Peter. After Jaslyn gives Peter all of her erasers and Peter gives Jaslyn 75% of his beads, Peter has 10 less beads than erasers. Find the number of beads Jaslyn has at first.

Jaslyn		Peter
Beads	Erasers	Beads	Erasers
2.8 u + 84	1 u	2 u + 60	2 u
+ 1.5 u + 45	- 1 u	- 1.5 u - 45	+ 1 u
4.3 u + 129	0	0.5 u + 15	3 u

100%+ 40% = 140% 

140% x 2 u
= ¹⁴⁰₁₀₀ x 2 u
= 2.8 u

140% x 60
= ¹⁴⁰₁₀₀ x 60
= 84 

75% x 2 u
= ⁷⁵₁₀₀ x 2 u
= 1.5 u  

75% x 60 
= ⁷⁵₁₀₀ x 60
= 45 

If another 10 beads are given to Peter, he will have equal number of beads and erasers in the end.
3 u = 0.5 u + 15 + 10
3 u - 0.5 u = 25
2.5 u = 25

1 u = 25 ÷ 2.5 = 10

Number of beads that Jaslyn has at first
= 2.8 u + 84
= 2.8 x 10 + 84
= 28 + 84
= 112
 
Answer(s): 112