Jane and Pierre collect pens and beads. Pierre has 60 less pens than beads. Pierre has 5 times the number of pens Jane has, and Jane has 30% more beads than Pierre. After Jane gives Pierre all of her pens and Pierre gives Jane 70% of his beads, Pierre has 18 more pens than beads. Find the number of beads Jane has at first.

Jane		Pierre
Beads	Pens	Beads	Pens
6.5 u + 78	1 u	5 u + 60	5 u
+ 3.5 u + 42	- 1 u	- 3.5 u - 42	+ 1 u
10 u + 120	0	1.5 u + 18	6 u

100%+ 30% = 130% 

130% x 5 u
= ¹³⁰₁₀₀ x 5 u
= 6.5 u

130% x 60
= ¹³⁰₁₀₀ x 60
= 78 

70% x 5 u
= ⁷⁰₁₀₀ x 5 u
= 3.5 u  

70% x 60 
= ⁷⁰₁₀₀ x 60
= 42 

If another 18 beads are given to Pierre, he will have equal number of beads and pens in the end.
6 u = 1.5 u + 18 + 18
6 u - 1.5 u = 36
4.5 u = 36

1 u = 36 ÷ 4.5 = 8

Number of beads that Jane has at first
= 6.5 u + 78
= 6.5 x 8 + 78
= 52 + 78
= 130
 
Answer(s): 130