Yoko and Luke collect pencils and coins. Luke has 80 more coins than pencils. Luke has 5 times the number of pencils Yoko has, and Yoko has 30% more coins than Luke. After Yoko gives Luke all of her pencils and Luke gives Yoko 60% of his coins, Luke has 24 more pencils than coins. Find the number of coins Yoko has at first.

Yoko		Luke
Coins	Pencils	Coins	Pencils
6.5 u + 104	1 u	5 u + 80	5 u
+ 3 u + 48	- 1 u	- 3 u - 48	+ 1 u
9.5 u + 152	0	2 u + 32	6 u

100% + 30% = 130% 

130% x 5 u
= ¹³⁰₁₀₀ x 5 u
= 6.5 u

130% x 80
= ¹³⁰₁₀₀ x 80
= 104 

60% x 5 u
= ⁶⁰₁₀₀ x 5 u
= 3 u  

60% x 80 
= ⁶⁰₁₀₀ x 80
= 48 

If another 24 coins are given to Luke, he will have equal number of coins and pencils in the end.
6 u = 2 u + 32 + 24
6 u - 2 u = 56
4 u = 56

1 u = 56 ÷ 4 = 14

Number of coins that Yoko has at first
= 6.5 u + 104
= 6.5 x 14 + 104
= 91 + 104
= 195
 
Answer(s): 195