Kimberly and Bobby collect erasers and stickers. Bobby has 64 less erasers than stickers. Bobby has 2 times the number of erasers Kimberly has, and Kimberly has 25% more stickers than Bobby. After Kimberly gives Bobby all of her erasers and Bobby gives Kimberly 75% of his stickers, Bobby has 34 more erasers than stickers. Find the number of stickers Kimberly has at first.
Kimberly |
Bobby |
Stickers |
Erasers |
Stickers |
Erasers |
2.5 u + 80 |
1 u |
2 u + 64 |
2 u |
+ 1.5 u + 48 |
- 1 u |
- 1.5 u - 48 |
+ 1 u |
4 u + 128 |
0 |
0.5 u + 16 |
3 u |
100%+ 25% = 125%
125% x 2 u
=
125100 x 2 u
= 2.5 u
125% x 64
=
125100 x 64
= 80
75% x 2 u
=
75100 x 2 u
= 1.5 u
75% x 64
=
75100 x 64
= 48
If another 34 stickers are given to Bobby, he will have equal number of stickers and erasers in the end.
3 u = 0.5 u + 16 + 34
3 u - 0.5 u = 50
2.5 u = 50
1 u = 50 ÷ 2.5 = 20
Number of stickers that Kimberly has at first
= 2.5 u + 80
= 2.5 x 20 + 80
= 50 + 80
= 130
Answer(s): 130