Mary and George collect buttons and erasers. George has 50 more erasers than buttons. George has 3 times the number of buttons Mary has, and Mary has 20% more erasers than George. After Mary gives George all of her buttons and George gives Mary 60% of his erasers, George has 22 more buttons than erasers. Find the number of erasers Mary has at first.
Mary |
George |
Erasers |
Buttons |
Erasers |
Buttons |
3.6 u + 60 |
1 u |
3 u + 50 |
3 u |
+ 1.8 u + 30 |
- 1 u |
- 1.8 u - 30 |
+ 1 u |
5.4 u + 90 |
0 |
1.2 u + 20 |
4 u |
100% + 20% = 120%
120% x 3 u
=
120100 x 3 u
= 3.6 u
120% x 50
=
120100 x 50
= 60
60% x 3 u
=
60100 x 3 u
= 1.8 u
60% x 50
=
60100 x 50
= 30
If another 22 erasers are given to George, he will have equal number of erasers and buttons in the end.
4 u = 1.2 u + 20 + 22
4 u - 1.2 u = 42
2.8 u = 42
1 u = 42 ÷ 2.8 = 15
Number of erasers that Mary has at first
= 3.6 u + 60
= 3.6 x 15 + 60
= 54 + 60
= 114
Answer(s): 114