Opal and Oliver collect stickers and buttons. Oliver has 35 less stickers than buttons. Oliver has 4 times the number of stickers Opal has, and Opal has 40% more buttons than Oliver. After Opal gives Oliver all of her stickers and Oliver gives Opal 60% of his buttons, Oliver has 20 more stickers than buttons. Find the number of buttons Opal has at first.
Opal |
Oliver |
Buttons |
Stickers |
Buttons |
Stickers |
5.6 u + 49 |
1 u |
4 u + 35 |
4 u |
+ 2.4 u + 21 |
- 1 u |
- 2.4 u - 21 |
+ 1 u |
8 u + 70 |
0 |
1.6 u + 14 |
5 u |
100%+ 40% = 140%
140% x 4 u
=
140100 x 4 u
= 5.6 u
140% x 35
=
140100 x 35
= 49
60% x 4 u
=
60100 x 4 u
= 2.4 u
60% x 35
=
60100 x 35
= 21
If another 20 buttons are given to Oliver, he will have equal number of buttons and stickers in the end.
5 u = 1.6 u + 14 + 20
5 u - 1.6 u = 34
3.4 u = 34
1 u = 34 ÷ 3.4 = 10
Number of buttons that Opal has at first
= 5.6 u + 49
= 5.6 x 10 + 49
= 56 + 49
= 105
Answer(s): 105