Irene and Jack collect beads and coins. Jack has 96 less beads than coins. Jack has 2 times the number of beads Irene has, and Irene has 25% more coins than Jack. After Irene gives Jack all of her beads and Jack gives Irene 75% of his coins, Jack has 11 more beads than coins. Find the number of coins Irene has at first.
Irene |
Jack |
Coins |
Beads |
Coins |
Beads |
2.5 u + 120 |
1 u |
2 u + 96 |
2 u |
+ 1.5 u + 72 |
- 1 u |
- 1.5 u - 72 |
+ 1 u |
4 u + 192 |
0 |
0.5 u + 24 |
3 u |
100%+ 25% = 125%
125% x 2 u
=
125100 x 2 u
= 2.5 u
125% x 96
=
125100 x 96
= 120
75% x 2 u
=
75100 x 2 u
= 1.5 u
75% x 96
=
75100 x 96
= 72
If another 11 coins are given to Jack, he will have equal number of coins and beads in the end.
3 u = 0.5 u + 24 + 11
3 u - 0.5 u = 35
2.5 u = 35
1 u = 35 ÷ 2.5 = 14
Number of coins that Irene has at first
= 2.5 u + 120
= 2.5 x 14 + 120
= 35 + 120
= 155
Answer(s): 155