Lynn and Brandon collect coins and erasers. Brandon has 40 less coins than erasers. Brandon has 2 times the number of coins Lynn has, and Lynn has 20% more erasers than Brandon. After Lynn gives Brandon all of her coins and Brandon gives Lynn 75% of his erasers, Brandon has 15 more coins than erasers. Find the number of erasers Lynn has at first.
Lynn |
Brandon |
Erasers |
Coins |
Erasers |
Coins |
2.4 u + 48 |
1 u |
2 u + 40 |
2 u |
+ 1.5 u + 30 |
- 1 u |
- 1.5 u - 30 |
+ 1 u |
3.9 u + 78 |
0 |
0.5 u + 10 |
3 u |
100%+ 20% = 120%
120% x 2 u
=
120100 x 2 u
= 2.4 u
120% x 40
=
120100 x 40
= 48
75% x 2 u
=
75100 x 2 u
= 1.5 u
75% x 40
=
75100 x 40
= 30
If another 15 erasers are given to Brandon, he will have equal number of erasers and coins in the end.
3 u = 0.5 u + 10 + 15
3 u - 0.5 u = 25
2.5 u = 25
1 u = 25 ÷ 2.5 = 10
Number of erasers that Lynn has at first
= 2.4 u + 48
= 2.4 x 10 + 48
= 24 + 48
= 72
Answer(s): 72