Julie and Ahmad collect pencils and coins. Ahmad has 40 less pencils than coins. Ahmad has 5 times the number of pencils Julie has, and Julie has 30% more coins than Ahmad. After Julie gives Ahmad all of her pencils and Ahmad gives Julie 70% of his coins, Ahmad has 69 more pencils than coins. Find the number of coins Julie has at first.

Julie		Ahmad
Coins	Pencils	Coins	Pencils
6.5 u + 52	1 u	5 u + 40	5 u
+ 3.5 u + 28	- 1 u	- 3.5 u - 28	+ 1 u
10 u + 80	0	1.5 u + 12	6 u

100%+ 30% = 130% 

130% x 5 u
= ¹³⁰₁₀₀ x 5 u
= 6.5 u

130% x 40
= ¹³⁰₁₀₀ x 40
= 52 

70% x 5 u
= ⁷⁰₁₀₀ x 5 u
= 3.5 u  

70% x 40 
= ⁷⁰₁₀₀ x 40
= 28 

If another 69 coins are given to Ahmad, he will have equal number of coins and pencils in the end.
6 u = 1.5 u + 12 + 69
6 u - 1.5 u = 81
4.5 u = 81

1 u = 81 ÷ 4.5 = 18

Number of coins that Julie has at first
= 6.5 u + 52
= 6.5 x 18 + 52
= 117 + 52
= 169
 
Answer(s): 169