Irene and Harry collect stickers and coins. Harry has 44 less stickers than coins. Harry has 2 times the number of stickers Irene has, and Irene has 25% more coins than Harry. After Irene gives Harry all of her stickers and Harry gives Irene 75% of his coins, Harry has 39 more stickers than coins. Find the number of coins Irene has at first.
Irene |
Harry |
Coins |
Stickers |
Coins |
Stickers |
2.5 u + 55 |
1 u |
2 u + 44 |
2 u |
+ 1.5 u + 33 |
- 1 u |
- 1.5 u - 33 |
+ 1 u |
4 u + 88 |
0 |
0.5 u + 11 |
3 u |
100%+ 25% = 125%
125% x 2 u
=
125100 x 2 u
= 2.5 u
125% x 44
=
125100 x 44
= 55
75% x 2 u
=
75100 x 2 u
= 1.5 u
75% x 44
=
75100 x 44
= 33
If another 39 coins are given to Harry, he will have equal number of coins and stickers in the end.
3 u = 0.5 u + 11 + 39
3 u - 0.5 u = 50
2.5 u = 50
1 u = 50 ÷ 2.5 = 20
Number of coins that Irene has at first
= 2.5 u + 55
= 2.5 x 20 + 55
= 50 + 55
= 105
Answer(s): 105