The ratio of the number of wafers in Container X to the number of wafers in Container Y was 9 : 5. 20% of the wafers in Container X and 0.7 of those in Container Y were vanilla. After transferring the wafers between the 2 boxes, the number of cherry wafers in both boxes are the same. Likewise, the number of vanilla wafers in both boxes are the same. If a total of 222 wafers were moved, how many more wafers were there in Container X than Container Y at first?

Container X		Container Y
9 u		5 u
Vanilla	Cherry	Vanilla	Cherry
1.8 u	7.2 u	3.5 u	1.5 u
+ 0.85 u	- 2.85 u	- 0.85 u	+ 2.85 u
2.65 u	4.35 u	2.65 u	4.35 u

Number of vanilla wafers in Container X
= 20% x 9 u
= ²⁰₁₀₀ x 9 u
= 1.8 u

Number of cherry wafers in Container X
= 9 u - 1.8 u
= 7.2 u

Number of vanilla wafers in Container Y
= 0.7 x 5 u
= 3.5 u

Number of cherry wafers in Container Y
= 5 u - 3.5 u
= 1.5 u

Number of vanilla wafers in each box in the end
= (1.8 u + 3.5 u) ÷ 2
= 5.3 u ÷ 2
= 2.65 u

Number of cherry wafers in each box in the end
= (7.2 u + 1.5 u) ÷ 2
= 8.7 u ÷ 2
= 4.35 u

Number of wafers moved
= 0.85 u + 2.85 u
= 3.7 u

3.7 u = 222

1 u = 222 ÷ 3.7 = 60

Number of more wafers in Container X than Container Y at first
= 9 u - 5 u
= 4 u
= 4 x 60
= 240

Answer(s): 240