The ratio of the number of tarts in Container M to the number of tarts in Container N was 7 : 5. 20% of the tarts in Container M and 0.6 of those in Container N were matcha. After transferring the tarts between the 2 boxes, the number of peach tarts in both boxes are the same. Likewise, the number of matcha tarts in both boxes are the same. If a total of 169 tarts were moved, how many more tarts were there in Container M than Container N at first?
Container M |
Container N |
7 u |
5 u |
Matcha |
Peach |
Matcha |
Peach |
1.4 u |
5.6 u |
3 u |
2 u |
+ 0.8 u |
- 1.8 u |
- 0.8 u |
+ 1.8 u |
2.2 u |
3.8 u |
2.2 u |
3.8 u |
Number of matcha tarts in Container M
= 20% x 7 u
=
20100 x 7 u
= 1.4 u
Number of peach tarts in Container M
= 7 u - 1.4 u
= 5.6 u
Number of matcha tarts in Container N
= 0.6 x 5 u
= 3 u
Number of peach tarts in Container N
= 5 u - 3 u
= 2 u
Number of matcha tarts in each box in the end
= (1.4 u + 3 u) ÷ 2
= 4.4 u ÷ 2
= 2.2 u
Number of peach tarts in each box in the end
= (5.6 u + 2 u) ÷ 2
= 7.6 u ÷ 2
= 3.8 u
Number of tarts moved
= 0.8 u + 1.8 u
= 2.6 u
2.6 u = 169
1 u = 169 ÷ 2.6 = 65
Number of more tarts in Container M than Container N at first
= 7 u - 5 u
= 2 u
= 2 x 65
= 130
Answer(s): 130