The ratio of the number of biscuits in Container H to the number of biscuits in Container J was 7 : 5. 20% of the biscuits in Container H and 0.6 of those in Container J were strawberry. After transferring the biscuits between the 2 containers, the number of mango biscuits in both containers are the same. Likewise, the number of strawberry biscuits in both containers are the same. If a total of 273 biscuits were moved, how many more biscuits were there in Container H than Container J at first?

Container H		Container J
7 u		5 u
Strawberry	Mango	Strawberry	Mango
1.4 u	5.6 u	3 u	2 u
+ 0.8 u	- 1.8 u	- 0.8 u	+ 1.8 u
2.2 u	3.8 u	2.2 u	3.8 u

Number of strawberry biscuits in Container H
= 20% x 7 u
= ²⁰₁₀₀ x 7 u
= 1.4 u

Number of mango biscuits in Container H
= 7 u - 1.4 u
= 5.6 u

Number of strawberry biscuits in Container J
= 0.6 x 5 u
= 3 u

Number of mango biscuits in Container J
= 5 u - 3 u
= 2 u

Number of strawberry biscuits in each container in the end
= (1.4 u + 3 u) ÷ 2
= 4.4 u ÷ 2
= 2.2 u

Number of mango biscuits in each container in the end
= (5.6 u + 2 u) ÷ 2
= 7.6 u ÷ 2
= 3.8 u

Number of biscuits moved
= 0.8 u + 1.8 u
= 2.6 u

2.6 u = 273

1 u = 273 ÷ 2.6 = 105

Number of more biscuits in Container H than Container J at first
= 7 u - 5 u
= 2 u
= 2 x 105
= 210

Answer(s): 210