The ratio of the number of biscuits in Container L to the number of biscuits in Container M was 5 : 3. 20% of the biscuits in Container L and 0.6 of those in Container M were vanilla. After transferring the biscuits between the 2 containers, the number of mango biscuits in both containers are the same. Likewise, the number of vanilla biscuits in both containers are the same. If a total of 171 biscuits were moved, how many more biscuits were there in Container L than Container M at first?

Container L		Container M
5 u		3 u
Vanilla	Mango	Vanilla	Mango
1 u	4 u	1.8 u	1.2 u
+ 0.4 u	- 1.4 u	- 0.4 u	+ 1.4 u
1.4 u	2.6 u	1.4 u	2.6 u

Number of vanilla biscuits in Container L
= 20% x 5 u
= ²⁰₁₀₀ x 5 u
= 1 u

Number of mango biscuits in Container L
= 5 u - 1 u
= 4 u

Number of vanilla biscuits in Container M
= 0.6 x 3 u
= 1.8 u

Number of mango biscuits in Container M
= 3 u - 1.8 u
= 1.2 u

Number of vanilla biscuits in each container in the end
= (1 u + 1.8 u) ÷ 2
= 2.8 u ÷ 2
= 1.4 u

Number of mango biscuits in each container in the end
= (4 u + 1.2 u) ÷ 2
= 5.2 u ÷ 2
= 2.6 u

Number of biscuits moved
= 0.4 u + 1.4 u
= 1.8 u

1.8 u = 171

1 u = 171 ÷ 1.8 = 95

Number of more biscuits in Container L than Container M at first
= 5 u - 3 u
= 2 u
= 2 x 95
= 190

Answer(s): 190