The ratio of the number of tarts in Container R to the number of tarts in Container S was 7 : 3. 20% of the tarts in Container R and 0.8 of those in Container S were mocha. After transferring the tarts between the 2 boxes, the number of butter cream tarts in both boxes are the same. Likewise, the number of mocha tarts in both boxes are the same. If a total of 264 tarts were moved, how many more tarts were there in Container R than Container S at first?

Container R		Container S
7 u		3 u
Mocha	Butter Cream	Mocha	Butter Cream
1.4 u	5.6 u	2.4 u	0.6 u
+ 0.5 u	- 2.5 u	- 0.5 u	+ 2.5 u
1.9 u	3.1 u	1.9 u	3.1 u

Number of mocha tarts in Container R
= 20% x 7 u
= ²⁰₁₀₀ x 7 u
= 1.4 u

Number of butter cream tarts in Container R
= 7 u - 1.4 u
= 5.6 u

Number of mocha tarts in Container S
= 0.8 x 3 u
= 2.4 u

Number of butter cream tarts in Container S
= 3 u - 2.4 u
= 0.6 u

Number of mocha tarts in each box in the end
= (1.4 u + 2.4 u) ÷ 2
= 3.8 u ÷ 2
= 1.9 u

Number of butter cream tarts in each box in the end
= (5.6 u + 0.6 u) ÷ 2
= 6.2 u ÷ 2
= 3.1 u

Number of tarts moved
= 0.5 u + 2.5 u
= 3 u

3 u = 264

1 u = 264 ÷ 3 = 88

Number of more tarts in Container R than Container S at first
= 7 u - 3 u
= 4 u
= 4 x 88
= 352

Answer(s): 352