Pamela had some grey beads and yellow beads in 2 packets. In Packet D, the ratio of the number of grey beads to yellow beads was 8 : 7. In Packet E, the number of grey beads was 4 times the number of yellow beads. Pamela transferred
27 of the yellow beads from Packet D to Packet E. The number of beads in Packet D became 182 and the ratio of the number of grey beads to yellow beads in Packet E became 8 : 9.
- How many yellow beads were transferred from Packet D to Packet E?
- What was the number of beads in Packet E after the transfer?
|
Packet D |
Packet E |
|
Grey |
Yellow |
Grey |
Yellow |
Comparing grey beads and yellow beads at first |
8 u |
7 u |
4x2 = 8 p |
1x2 = 2 p |
Before |
|
7 u |
|
|
Change |
|
- 2 u |
|
+ 2 u |
After |
|
5 u |
|
|
Comparing grey beads and yellow beads in the end |
8 u |
5 u |
8 p |
9 p |
(a)
Total number of beads in the end for Packet D
= 8 u + 5 u
= 13 u
13 u = 182
1 u = 182 ÷ 13 = 14
Number of yellow beads that were transferred from Packet D to Packet E
= 2 u
= 2 x 14
= 28
(b)
The number of grey beads in Packet E remains unchanged. Make the number of grey beads in Packet E the same. LCM of 4 and 8 is 8.
Increase in the number of yellow beads in Packet E
= 9 p - 2 p
= 7 p
7 p = 2 u
7 p = 28
1 p = 28 ÷ 7 = 4
Number of beads in Packet E in the end
= 8 p + 9 p
= 17 p
= 17 x 4
= 68
Answer(s): (a) 28; (b) 68