Esther had some purple pens and brown pens in 2 packets. In Packet A, the ratio of the number of purple pens to brown pens was 10 : 3. In Packet B, the number of purple pens was 2 times the number of brown pens. Esther transferred
23 of the brown pens from Packet A to Packet B. The number of pens in Packet A became 198 and the ratio of the number of purple pens to brown pens in Packet B became 4 : 5.
- How many brown pens were transferred from Packet A to Packet B?
- What was the number of pens in Packet B after the transfer?
|
Packet A |
Packet B |
|
Purple |
Brown |
Purple |
Brown |
Comparing purple pens and brown pens at first |
10 u |
3 u |
2x2 = 4 p |
1x2 = 2 p |
Before |
|
3 u |
|
|
Change |
|
- 2 u |
|
+ 2 u |
After |
|
1 u |
|
|
Comparing purple pens and brown pens in the end |
10 u |
1 u |
4 p |
5 p |
(a)
Total number of pens in the end for Packet A
= 10 u + 1 u
= 11 u
11 u = 198
1 u = 198 ÷ 11 = 18
Number of brown pens that were transferred from Packet A to Packet B
= 2 u
= 2 x 18
= 36
(b)
The number of purple pens in Packet B remains unchanged. Make the number of purple pens in Packet B the same. LCM of 2 and 4 is 4.
Increase in the number of brown pens in Packet B
= 5 p - 2 p
= 3 p
3 p = 2 u
3 p = 36
1 p = 36 ÷ 3 = 12
Number of pens in Packet B in the end
= 4 p + 5 p
= 9 p
= 9 x 12
= 108
Answer(s): (a) 36; (b) 108