Xuan had some white beads and gold beads in 2 bags. In Bag T, the ratio of the number of white beads to gold beads was 7 : 5. In Bag U, the number of white beads was 2 times the number of gold beads. Xuan transferred
35 of the gold beads from Bag T to Bag U. The number of beads in Bag T became 36 and the ratio of the number of white beads to gold beads in Bag U became 6 : 7.
- How many gold beads were transferred from Bag T to Bag U?
- What was the number of beads in Bag U after the transfer?
|
Bag T |
Bag U |
|
White |
Gold |
White |
Gold |
Comparing white beads and gold beads at first |
7 u |
5 u |
2x3 = 6 p |
1x3 = 3 p |
Before |
|
5 u |
|
|
Change |
|
- 3 u |
|
+ 3 u |
After |
|
2 u |
|
|
Comparing white beads and gold beads in the end |
7 u |
2 u |
6 p |
7 p |
(a)
Total number of beads in the end for Bag T
= 7 u + 2 u
= 9 u
9 u = 36
1 u = 36 ÷ 9 = 4
Number of gold beads that were transferred from Bag T to Bag U
= 3 u
= 3 x 4
= 12
(b)
The number of white beads in Bag U remains unchanged. Make the number of white beads in Bag U the same. LCM of 2 and 6 is 6.
Increase in the number of gold beads in Bag U
= 7 p - 3 p
= 4 p
4 p = 3 u
4 p = 12
1 p = 12 ÷ 4 = 3
Number of beads in Bag U in the end
= 6 p + 7 p
= 13 p
= 13 x 3
= 39
Answer(s): (a) 12; (b) 39