Jen had some purple pens and green pens in 2 bags. In Bag N, the ratio of the number of purple pens to green pens was 9 : 7. In Bag P, the number of purple pens was 2 times the number of green pens. Jen transferred
27 of the green pens from Bag N to Bag P. The number of pens in Bag N became 252 and the ratio of the number of purple pens to green pens in Bag P became 4 : 5.
- How many green pens were transferred from Bag N to Bag P?
- What was the number of pens in Bag P after the transfer?
|
Bag N |
Bag P |
|
Purple |
Green |
Purple |
Green |
Comparing purple pens and green pens at first |
9 u |
7 u |
2x2 = 4 p |
1x2 = 2 p |
Before |
|
7 u |
|
|
Change |
|
- 2 u |
|
+ 2 u |
After |
|
5 u |
|
|
Comparing purple pens and green pens in the end |
9 u |
5 u |
4 p |
5 p |
(a)
Total number of pens in the end for Bag N
= 9 u + 5 u
= 14 u
14 u = 252
1 u = 252 ÷ 14 = 18
Number of green pens that were transferred from Bag N to Bag P
= 2 u
= 2 x 18
= 36
(b)
The number of purple pens in Bag P remains unchanged. Make the number of purple pens in Bag P the same. LCM of 2 and 4 is 4.
Increase in the number of green pens in Bag P
= 5 p - 2 p
= 3 p
3 p = 2 u
3 p = 36
1 p = 36 ÷ 3 = 12
Number of pens in Bag P in the end
= 4 p + 5 p
= 9 p
= 9 x 12
= 108
Answer(s): (a) 36; (b) 108