Emily had some silver stamps and black stamps in 2 packets. In Packet X, the ratio of the number of silver stamps to black stamps was 8 : 5. In Packet Y, the number of silver stamps was 4 times the number of black stamps. Emily transferred
25 of the black stamps from Packet X to Packet Y. The number of stamps in Packet X became 77 and the ratio of the number of silver stamps to black stamps in Packet Y became 8 : 9.
- How many black stamps were transferred from Packet X to Packet Y?
- What was the number of stamps in Packet Y after the transfer?
|
Packet X |
Packet Y |
|
Silver |
Black |
Silver |
Black |
Comparing silver stamps and black stamps at first |
8 u |
5 u |
4x2 = 8 p |
1x2 = 2 p |
Before |
|
5 u |
|
|
Change |
|
- 2 u |
|
+ 2 u |
After |
|
3 u |
|
|
Comparing silver stamps and black stamps in the end |
8 u |
3 u |
8 p |
9 p |
(a)
Total number of stamps in the end for Packet X
= 8 u + 3 u
= 11 u
11 u = 77
1 u = 77 ÷ 11 = 7
Number of black stamps that were transferred from Packet X to Packet Y
= 2 u
= 2 x 7
= 14
(b)
The number of silver stamps in Packet Y remains unchanged. Make the number of silver stamps in Packet Y the same. LCM of 4 and 8 is 8.
Increase in the number of black stamps in Packet Y
= 9 p - 2 p
= 7 p
7 p = 2 u
7 p = 14
1 p = 14 ÷ 7 = 2
Number of stamps in Packet Y in the end
= 8 p + 9 p
= 17 p
= 17 x 2
= 34
Answer(s): (a) 14; (b) 34