Ivory had some brown buttons and grey buttons in 2 boxes. In Box Q, the ratio of the number of brown buttons to grey buttons was 10 : 3. In Box R, the number of brown buttons was 2 times the number of grey buttons. Ivory transferred
23 of the grey buttons from Box Q to Box R. The number of buttons in Box Q became 132 and the ratio of the number of brown buttons to grey buttons in Box R became 4 : 5.
- How many grey buttons were transferred from Box Q to Box R?
- What was the number of buttons in Box R after the transfer?
|
Box Q |
Box R |
|
Brown |
Grey |
Brown |
Grey |
Comparing brown buttons and grey buttons at first |
10 u |
3 u |
2x2 = 4 p |
1x2 = 2 p |
Before |
|
3 u |
|
|
Change |
|
- 2 u |
|
+ 2 u |
After |
|
1 u |
|
|
Comparing brown buttons and grey buttons in the end |
10 u |
1 u |
4 p |
5 p |
(a)
Total number of buttons in the end for Box Q
= 10 u + 1 u
= 11 u
11 u = 132
1 u = 132 ÷ 11 = 12
Number of grey buttons that were transferred from Box Q to Box R
= 2 u
= 2 x 12
= 24
(b)
The number of brown buttons in Box R remains unchanged. Make the number of brown buttons in Box R the same. LCM of 2 and 4 is 4.
Increase in the number of grey buttons in Box R
= 5 p - 2 p
= 3 p
3 p = 2 u
3 p = 24
1 p = 24 ÷ 3 = 8
Number of buttons in Box R in the end
= 4 p + 5 p
= 9 p
= 9 x 8
= 72
Answer(s): (a) 24; (b) 72