Victoria had some yellow buttons and red buttons in 2 packets. In Packet F, the ratio of the number of yellow buttons to red buttons was 8 : 3. In Packet G, the number of yellow buttons was 2 times the number of red buttons. Victoria transferred
23 of the red buttons from Packet F to Packet G. The number of buttons in Packet F became 54 and the ratio of the number of yellow buttons to red buttons in Packet G became 4 : 5.
- How many red buttons were transferred from Packet F to Packet G?
- What was the number of buttons in Packet G after the transfer?
|
Packet F |
Packet G |
|
Yellow |
Red |
Yellow |
Red |
Comparing yellow buttons and red buttons at first |
8 u |
3 u |
2x2 = 4 p |
1x2 = 2 p |
Before |
|
3 u |
|
|
Change |
|
- 2 u |
|
+ 2 u |
After |
|
1 u |
|
|
Comparing yellow buttons and red buttons in the end |
8 u |
1 u |
4 p |
5 p |
(a)
Total number of buttons in the end for Packet F
= 8 u + 1 u
= 9 u
9 u = 54
1 u = 54 ÷ 9 = 6
Number of red buttons that were transferred from Packet F to Packet G
= 2 u
= 2 x 6
= 12
(b)
The number of yellow buttons in Packet G remains unchanged. Make the number of yellow buttons in Packet G the same. LCM of 2 and 4 is 4.
Increase in the number of red buttons in Packet G
= 5 p - 2 p
= 3 p
3 p = 2 u
3 p = 12
1 p = 12 ÷ 3 = 4
Number of buttons in Packet G in the end
= 4 p + 5 p
= 9 p
= 9 x 4
= 36
Answer(s): (a) 12; (b) 36