Barbara had some grey stickers and pink stickers in 2 bags. In Bag G, the ratio of the number of grey stickers to pink stickers was 9 : 5. In Bag H, the number of grey stickers was 2 times the number of pink stickers. Barbara transferred
45 of the pink stickers from Bag G to Bag H. The number of stickers in Bag G became 60 and the ratio of the number of grey stickers to pink stickers in Bag H became 4 : 5.
- How many pink stickers were transferred from Bag G to Bag H?
- What was the number of stickers in Bag H after the transfer?
|
Bag G |
Bag H |
|
Grey |
Pink |
Grey |
Pink |
Comparing grey stickers and pink stickers at first |
9 u |
5 u |
2x2 = 4 p |
1x2 = 2 p |
Before |
|
5 u |
|
|
Change |
|
- 4 u |
|
+ 4 u |
After |
|
1 u |
|
|
Comparing grey stickers and pink stickers in the end |
9 u |
1 u |
4 p |
5 p |
(a)
Total number of stickers in the end for Bag G
= 9 u + 1 u
= 10 u
10 u = 60
1 u = 60 ÷ 10 = 6
Number of pink stickers that were transferred from Bag G to Bag H
= 4 u
= 4 x 6
= 24
(b)
The number of grey stickers in Bag H remains unchanged. Make the number of grey stickers in Bag H the same. LCM of 2 and 4 is 4.
Increase in the number of pink stickers in Bag H
= 5 p - 2 p
= 3 p
3 p = 4 u
3 p = 24
1 p = 24 ÷ 3 = 8
Number of stickers in Bag H in the end
= 4 p + 5 p
= 9 p
= 9 x 8
= 72
Answer(s): (a) 24; (b) 72