Xylia had some yellow pens and silver pens in 2 packets. In Packet P, the ratio of the number of yellow pens to silver pens was 8 : 7. In Packet Q, the number of yellow pens was 2 times the number of silver pens. Xylia transferred
27 of the silver pens from Packet P to Packet Q. The number of pens in Packet P became 234 and the ratio of the number of yellow pens to silver pens in Packet Q became 4 : 5.
- How many silver pens were transferred from Packet P to Packet Q?
- What was the number of pens in Packet Q after the transfer?
|
Packet P |
Packet Q |
|
Yellow |
Silver |
Yellow |
Silver |
Comparing yellow pens and silver pens at first |
8 u |
7 u |
2x2 = 4 p |
1x2 = 2 p |
Before |
|
7 u |
|
|
Change |
|
- 2 u |
|
+ 2 u |
After |
|
5 u |
|
|
Comparing yellow pens and silver pens in the end |
8 u |
5 u |
4 p |
5 p |
(a)
Total number of pens in the end for Packet P
= 8 u + 5 u
= 13 u
13 u = 234
1 u = 234 ÷ 13 = 18
Number of silver pens that were transferred from Packet P to Packet Q
= 2 u
= 2 x 18
= 36
(b)
The number of yellow pens in Packet Q remains unchanged. Make the number of yellow pens in Packet Q the same. LCM of 2 and 4 is 4.
Increase in the number of silver pens in Packet Q
= 5 p - 2 p
= 3 p
3 p = 2 u
3 p = 36
1 p = 36 ÷ 3 = 12
Number of pens in Packet Q in the end
= 4 p + 5 p
= 9 p
= 9 x 12
= 108
Answer(s): (a) 36; (b) 108