Cathy had some yellow stickers and red stickers in 2 packets. In Packet D, the ratio of the number of yellow stickers to red stickers was 8 : 5. In Packet E, the number of yellow stickers was 2 times the number of red stickers. Cathy transferred ²₅ of the red stickers from Packet D to Packet E. The number of stickers in Packet D became 220 and the ratio of the number of yellow stickers to red stickers in Packet E became 6 : 7.

1. How many red stickers were transferred from Packet D to Packet E?
2. What was the number of stickers in Packet E after the transfer?

	Packet D		Packet E
	Yellow	Red	Yellow	Red
Comparing yellow stickers and red stickers at first	8 u	5 u	2x3 = 6 p	1x3 = 3 p
Before		5 u
Change		- 2 u		+ 2 u
After		3 u
Comparing yellow stickers and red stickers in the end	8 u	3 u	6 p	7 p

(a)
Total number of stickers in the end for Packet D
= 8 u + 3 u
= 11 u

11 u = 220

1 u = 220 ÷ 11 = 20

Number of red stickers that were transferred from Packet D to Packet E
= 2 u
= 2 x 20
= 40

(b)
The number of yellow stickers in Packet E remains unchanged.  Make the number of yellow stickers in Packet E the same.  LCM of 2 and 6 is 6. 

Increase in the number of red stickers in Packet E
= 7 p - 3 p
= 4 p

4 p = 2 u
4 p = 40

1 p = 40 ÷ 4 = 10

Number of stickers in Packet E in the end
= 6 p + 7 p
= 13 p
= 13 x 10
= 130

Answer(s): (a) 40; (b) 130