Xuan had some red stickers and purple stickers in 2 bags. In Bag E, the ratio of the number of red stickers to purple stickers was 10 : 3. In Bag F, the number of red stickers was 2 times the number of purple stickers. Xuan transferred
23 of the purple stickers from Bag E to Bag F. The number of stickers in Bag E became 165 and the ratio of the number of red stickers to purple stickers in Bag F became 4 : 5.
- How many purple stickers were transferred from Bag E to Bag F?
- What was the number of stickers in Bag F after the transfer?
|
Bag E |
Bag F |
|
Red |
Purple |
Red |
Purple |
Comparing red stickers and purple stickers at first |
10 u |
3 u |
2x2 = 4 p |
1x2 = 2 p |
Before |
|
3 u |
|
|
Change |
|
- 2 u |
|
+ 2 u |
After |
|
1 u |
|
|
Comparing red stickers and purple stickers in the end |
10 u |
1 u |
4 p |
5 p |
(a)
Total number of stickers in the end for Bag E
= 10 u + 1 u
= 11 u
11 u = 165
1 u = 165 ÷ 11 = 15
Number of purple stickers that were transferred from Bag E to Bag F
= 2 u
= 2 x 15
= 30
(b)
The number of red stickers in Bag F remains unchanged. Make the number of red stickers in Bag F the same. LCM of 2 and 4 is 4.
Increase in the number of purple stickers in Bag F
= 5 p - 2 p
= 3 p
3 p = 2 u
3 p = 30
1 p = 30 ÷ 3 = 10
Number of stickers in Bag F in the end
= 4 p + 5 p
= 9 p
= 9 x 10
= 90
Answer(s): (a) 30; (b) 90