Jade had some white stamps and green stamps in 2 packets. In Packet A, the ratio of the number of white stamps to green stamps was 10 : 3. In Packet B, the number of white stamps was 2 times the number of green stamps. Jade transferred
23 of the green stamps from Packet A to Packet B. The number of stamps in Packet A became 165 and the ratio of the number of white stamps to green stamps in Packet B became 4 : 5.
- How many green stamps were transferred from Packet A to Packet B?
- What was the number of stamps in Packet B after the transfer?
|
Packet A |
Packet B |
|
White |
Green |
White |
Green |
Comparing white stamps and green stamps at first |
10 u |
3 u |
2x2 = 4 p |
1x2 = 2 p |
Before |
|
3 u |
|
|
Change |
|
- 2 u |
|
+ 2 u |
After |
|
1 u |
|
|
Comparing white stamps and green stamps in the end |
10 u |
1 u |
4 p |
5 p |
(a)
Total number of stamps in the end for Packet A
= 10 u + 1 u
= 11 u
11 u = 165
1 u = 165 ÷ 11 = 15
Number of green stamps that were transferred from Packet A to Packet B
= 2 u
= 2 x 15
= 30
(b)
The number of white stamps in Packet B remains unchanged. Make the number of white stamps in Packet B the same. LCM of 2 and 4 is 4.
Increase in the number of green stamps in Packet B
= 5 p - 2 p
= 3 p
3 p = 2 u
3 p = 30
1 p = 30 ÷ 3 = 10
Number of stamps in Packet B in the end
= 4 p + 5 p
= 9 p
= 9 x 10
= 90
Answer(s): (a) 30; (b) 90