Jade had some red stickers and blue stickers in 2 boxes. In Box V, the ratio of the number of red stickers to blue stickers was 9 : 5. In Box W, the number of red stickers was 3 times the number of blue stickers. Jade transferred ²₅ of the blue stickers from Box V to Box W. The number of stickers in Box V became 240 and the ratio of the number of red stickers to blue stickers in Box W became 6 : 7.

1. How many blue stickers were transferred from Box V to Box W?
2. What was the number of stickers in Box W after the transfer?

	Box V		Box W
	Red	Blue	Red	Blue
Comparing red stickers and blue stickers at first	9 u	5 u	3x2 = 6 p	1x2 = 2 p
Before		5 u
Change		- 2 u		+ 2 u
After		3 u
Comparing red stickers and blue stickers in the end	9 u	3 u	6 p	7 p

(a)
Total number of stickers in the end for Box V
= 9 u + 3 u
= 12 u

12 u = 240

1 u = 240 ÷ 12 = 20

Number of blue stickers that were transferred from Box V to Box W
= 2 u
= 2 x 20
= 40

(b)
The number of red stickers in Box W remains unchanged.  Make the number of red stickers in Box W the same.  LCM of 3 and 6 is 6. 

Increase in the number of blue stickers in Box W
= 7 p - 2 p
= 5 p

5 p = 2 u
5 p = 40

1 p = 40 ÷ 5 = 8

Number of stickers in Box W in the end
= 6 p + 7 p
= 13 p
= 13 x 8
= 104

Answer(s): (a) 40; (b) 104