Marion spent $96 on some markers, notebooks and staplers. The number of markers she bought was
23 the number of notebooks. The number of staplers she bought was
34 the number of notebooks. The ratio of the amount of money she spent on the markers, notebooks and staplers was 2 : 7 : 7. The notebooks were sold at 2 for $7. Find the price of 1 marker.
Amount spent |
Markers |
Notebooks |
Staplers |
Total |
2 u |
7 u |
7 u |
$96 |
Total amount that Marion spent on markers, notebooks and staplers
= 2 u + 7 u + 7 u
= 16 u
16 u = 96
1 u = 96 ÷ 16 = 6
Amount that Marion spent on notebooks
= 7 u
= 7 x 6
= $42
Number of sets of notebooks of 2 bought
= 42 ÷ 7
= 6
Number of notebooks that Marion bought
= 6 x 2
= 12
Number of items bought |
Markers |
Notebooks |
Staplers |
Total |
2x4 |
3x4 |
|
|
|
4x3 |
3x3 |
|
8 p |
12 p |
9 p |
29 p |
The number of notebooks bought is repeated. Make the number of notebooks bought is the same. LCM of 3 and 4 is 12.
Number of notebooks that Marion bought = 12 p
12 p = 12
1 p = 12 ÷ 12 = 1
Number of markers that Marion bought
= 8 p
= 8 x 1
= 8
Amount that Marion spent on markers
= 2 u
= 2 x 6
= $12
Price of 1 marker
= 12 ÷ 8
= $1.50
Answer(s): $1.50