Jaslyn and Tiffany have some stickers. If Jaslyn gives 31 stickers to Tiffany, Tiffany will have 5 times the number of stickers as Jaslyn. If Tiffany gives 9 stickers to Jaslyn, Jaslyn will have
35 as many stickers as Tiffany. How many stickers does Jaslyn have at first?
| |
Case 1 |
Case 2 |
| |
Jaslyn |
Tiffany |
Jaslyn |
Tiffany |
| Before |
4 u + 31 |
20 u - 31 |
9 u - 9 |
15 u + 9 |
| Change |
- 31 |
+ 31 |
+ 9 |
- 9 |
| After |
1x4 =
4 u |
5x4 =
20 u |
3x3 =
9 u |
5x3 =
15 u |
The total number of stickers in both cases remains unchanged. Make the total number of stickers in both cases the same. LCM of 6 and 8 is 24.
Number of stickers that Jaslyn had at first is the same in both cases.
9 u - 9 = 4 u + 31
9 u - 4 u = 31 + 9
5 u = 40
1 u = 8
Number of stickers that Jaslyn had at first
= 4 u + 31
= 4 x 8 + 31
= 32 + 31
= 63
Answer(s): 63
