Nicole and Dana have some stickers. If Nicole gives 40 stickers to Dana, Dana will have 4 times the number of stickers as Nicole. If Dana gives 16 stickers to Nicole, Nicole will have
35 as many stickers as Dana. How many stickers does Nicole have at first?
|
Case 1 |
Case 2 |
|
Nicole |
Dana |
Nicole |
Dana |
Before |
8 u + 40 |
32 u - 40 |
15 u - 16 |
25 u + 16 |
Change |
- 40 |
+ 40 |
+ 16 |
- 16 |
After |
1x8 = 8 u |
4x8 = 32 u |
3x5 = 15 u |
5x5 = 25 u |
The total number of stickers in both cases remains unchanged. Make the total number of stickers in both cases the same. LCM of 5 and 8 is 40.
Number of stickers that Nicole had at first is the same in both cases.
15 u - 16 = 8 u + 40
15 u - 8 u = 40 + 16
7 u = 56
1 u = 8
Number of stickers that Nicole had at first
= 8 u + 40
= 8 x 8 + 40
= 64 + 40
= 104
Answer(s): 104