Jane and Winnie have some stickers. If Jane gives 27 stickers to Winnie, Winnie will have 3 times the number of stickers as Jane. If Winnie gives 33 stickers to Jane, Jane will have
23 as many stickers as Winnie. How many stickers does Jane have at first?
| |
Case 1 |
Case 2 |
| |
Jane |
Winnie |
Jane |
Winnie |
| Before |
5 u + 27 |
15 u - 27 |
8 u - 33 |
12 u + 33 |
| Change |
- 27 |
+ 27 |
+ 33 |
- 33 |
| After |
1x5 =
5 u |
3x5 =
15 u |
2x4 =
8 u |
3x4 =
12 u |
The total number of stickers in both cases remains unchanged. Make the total number of stickers in both cases the same. LCM of 4 and 5 is 20.
Number of stickers that Jane had at first is the same in both cases.
8 u - 33 = 5 u + 27
8 u - 5 u = 27 + 33
3 u = 60
1 u = 20
Number of stickers that Jane had at first
= 5 u + 27
= 5 x 20 + 27
= 100 + 27
= 127
Answer(s): 127
