Jaslyn and Rachel have some stickers. If Jaslyn gives 21 stickers to Rachel, Rachel will have 4 times the number of stickers as Jaslyn. If Rachel gives 35 stickers to Jaslyn, Jaslyn will have
35 as many stickers as Rachel. How many stickers does Jaslyn have at first?
|
Case 1 |
Case 2 |
|
Jaslyn |
Rachel |
Jaslyn |
Rachel |
Before |
8 u + 21 |
32 u - 21 |
15 u - 35 |
25 u + 35 |
Change |
- 21 |
+ 21 |
+ 35 |
- 35 |
After |
1x8 = 8 u |
4x8 = 32 u |
3x5 = 15 u |
5x5 = 25 u |
The total number of stickers in both cases remains unchanged. Make the total number of stickers in both cases the same. LCM of 5 and 8 is 40.
Number of stickers that Jaslyn had at first is the same in both cases.
15 u - 35 = 8 u + 21
15 u - 8 u = 21 + 35
7 u = 56
1 u = 8
Number of stickers that Jaslyn had at first
= 8 u + 21
= 8 x 8 + 21
= 64 + 21
= 85
Answer(s): 85