Xylia and Min have some coins. If Xylia gives 26 coins to Min, Min will have 5 times the number of coins as Xylia. If Min gives 74 coins to Xylia, Xylia will have
35 as many coins as Min. How many coins does Xylia have at first?
|
Case 1 |
Case 2 |
|
Xylia |
Min |
Xylia |
Min |
Before |
4 u + 26 |
20 u - 26 |
9 u - 74 |
15 u + 74 |
Change |
- 26 |
+ 26 |
+ 74 |
- 74 |
After |
1x4 = 4 u |
5x4 = 20 u |
3x3 = 9 u |
5x3 = 15 u |
The total number of coins in both cases remains unchanged. Make the total number of coins in both cases the same. LCM of 6 and 8 is 24.
Number of coins that Xylia had at first is the same in both cases.
9 u - 74 = 4 u + 26
9 u - 4 u = 26 + 74
5 u = 100
1 u = 20
Number of coins that Xylia had at first
= 4 u + 26
= 4 x 20 + 26
= 80 + 26
= 106
Answer(s): 106