Jen and Wendy have some stamps. If Jen gives 27 stamps to Wendy, Wendy will have 4 times the number of stamps as Jen. If Wendy gives 36 stamps to Jen, Jen will have
35 as many stamps as Wendy. How many stamps does Jen have at first?
| |
Case 1 |
Case 2 |
| |
Jen |
Wendy |
Jen |
Wendy |
| Before |
8 u + 27 |
32 u - 27 |
15 u - 36 |
25 u + 36 |
| Change |
- 27 |
+ 27 |
+ 36 |
- 36 |
| After |
1x8 =
8 u |
4x8 =
32 u |
3x5 =
15 u |
5x5 =
25 u |
The total number of stamps in both cases remains unchanged. Make the total number of stamps in both cases the same. LCM of 5 and 8 is 40.
Number of stamps that Jen had at first is the same in both cases.
15 u - 36 = 8 u + 27
15 u - 8 u = 27 + 36
7 u = 63
1 u = 9
Number of stamps that Jen had at first
= 8 u + 27
= 8 x 9 + 27
= 72 + 27
= 99
Answer(s): 99
