Tiffany and Lynn have some stickers. If Tiffany gives 12 stickers to Lynn, Lynn will have 5 times the number of stickers as Tiffany. If Lynn gives 23 stickers to Tiffany, Tiffany will have
23 as many stickers as Lynn. How many stickers does Tiffany have at first?
| |
Case 1 |
Case 2 |
| |
Tiffany |
Lynn |
Tiffany |
Lynn |
| Before |
5 u + 12 |
25 u - 12 |
12 u - 23 |
18 u + 23 |
| Change |
- 12 |
+ 12 |
+ 23 |
- 23 |
| After |
1x5 =
5 u |
5x5 =
25 u |
2x6 =
12 u |
3x6 =
18 u |
The total number of stickers in both cases remains unchanged. Make the total number of stickers in both cases the same. LCM of 6 and 5 is 30.
Number of stickers that Tiffany had at first is the same in both cases.
12 u - 23 = 5 u + 12
12 u - 5 u = 12 + 23
7 u = 35
1 u = 5
Number of stickers that Tiffany had at first
= 5 u + 12
= 5 x 5 + 12
= 25 + 12
= 37
Answer(s): 37
