Kylie and Kimberly have some marbles. If Kylie gives 28 marbles to Kimberly, Kimberly will have 5 times the number of marbles as Kylie. If Kimberly gives 63 marbles to Kylie, Kylie will have
23 as many marbles as Kimberly. How many marbles does Kylie have at first?
|
Case 1 |
Case 2 |
|
Kylie |
Kimberly |
Kylie |
Kimberly |
Before |
5 u + 28 |
25 u - 28 |
12 u - 63 |
18 u + 63 |
Change |
- 28 |
+ 28 |
+ 63 |
- 63 |
After |
1x5 = 5 u |
5x5 = 25 u |
2x6 = 12 u |
3x6 = 18 u |
The total number of marbles in both cases remains unchanged. Make the total number of marbles in both cases the same. LCM of 6 and 5 is 30.
Number of marbles that Kylie had at first is the same in both cases.
12 u - 63 = 5 u + 28
12 u - 5 u = 28 + 63
7 u = 91
1 u = 13
Number of marbles that Kylie had at first
= 5 u + 28
= 5 x 13 + 28
= 65 + 28
= 93
Answer(s): 93