Barbara and Joelle have some stickers. If Barbara gives 26 stickers to Joelle, Joelle will have 3 times the number of stickers as Barbara. If Joelle gives 4 stickers to Barbara, Barbara will have
23 as many stickers as Joelle. How many stickers does Barbara have at first?
|
Case 1 |
Case 2 |
|
Barbara |
Joelle |
Barbara |
Joelle |
Before |
5 u + 26 |
15 u - 26 |
8 u - 4 |
12 u + 4 |
Change |
- 26 |
+ 26 |
+ 4 |
- 4 |
After |
1x5 = 5 u |
3x5 = 15 u |
2x4 = 8 u |
3x4 = 12 u |
The total number of stickers in both cases remains unchanged. Make the total number of stickers in both cases the same. LCM of 4 and 5 is 20.
Number of stickers that Barbara had at first is the same in both cases.
8 u - 4 = 5 u + 26
8 u - 5 u = 26 + 4
3 u = 30
1 u = 10
Number of stickers that Barbara had at first
= 5 u + 26
= 5 x 10 + 26
= 50 + 26
= 76
Answer(s): 76