Emma and Opal have some stickers. If Emma gives 19 stickers to Opal, Opal will have 5 times the number of stickers as Emma. If Opal gives 36 stickers to Emma, Emma will have
35 as many stickers as Opal. How many stickers does Emma have at first?
|
Case 1 |
Case 2 |
|
Emma |
Opal |
Emma |
Opal |
Before |
4 u + 19 |
20 u - 19 |
9 u - 36 |
15 u + 36 |
Change |
- 19 |
+ 19 |
+ 36 |
- 36 |
After |
1x4 = 4 u |
5x4 = 20 u |
3x3 = 9 u |
5x3 = 15 u |
The total number of stickers in both cases remains unchanged. Make the total number of stickers in both cases the same. LCM of 6 and 8 is 24.
Number of stickers that Emma had at first is the same in both cases.
9 u - 36 = 4 u + 19
9 u - 4 u = 19 + 36
5 u = 55
1 u = 11
Number of stickers that Emma had at first
= 4 u + 19
= 4 x 11 + 19
= 44 + 19
= 63
Answer(s): 63