Jaslyn and Marion have some cards. If Jaslyn gives 20 cards to Marion, Marion will have 4 times the number of cards as Jaslyn. If Marion gives 36 cards to Jaslyn, Jaslyn will have
35 as many cards as Marion. How many cards does Jaslyn have at first?
|
Case 1 |
Case 2 |
|
Jaslyn |
Marion |
Jaslyn |
Marion |
Before |
8 u + 20 |
32 u - 20 |
15 u - 36 |
25 u + 36 |
Change |
- 20 |
+ 20 |
+ 36 |
- 36 |
After |
1x8 = 8 u |
4x8 = 32 u |
3x5 = 15 u |
5x5 = 25 u |
The total number of cards in both cases remains unchanged. Make the total number of cards in both cases the same. LCM of 5 and 8 is 40.
Number of cards that Jaslyn had at first is the same in both cases.
15 u - 36 = 8 u + 20
15 u - 8 u = 20 + 36
7 u = 56
1 u = 8
Number of cards that Jaslyn had at first
= 8 u + 20
= 8 x 8 + 20
= 64 + 20
= 84
Answer(s): 84