Roshel and Barbara have some stickers. If Roshel gives 22 stickers to Barbara, Barbara will have 5 times the number of stickers as Roshel. If Barbara gives 73 stickers to Roshel, Roshel will have
25 as many stickers as Barbara. How many stickers does Roshel have at first?
|
Case 1 |
Case 2 |
|
Roshel |
Barbara |
Roshel |
Barbara |
Before |
7 u + 22 |
35 u - 22 |
12 u - 73 |
30 u + 73 |
Change |
- 22 |
+ 22 |
+ 73 |
- 73 |
After |
1x7 = 7 u |
5x7 = 35 u |
2x6 = 12 u |
5x6 = 30 u |
The total number of stickers in both cases remains unchanged. Make the total number of stickers in both cases the same. LCM of 6 and 7 is 42.
Number of stickers that Roshel had at first is the same in both cases.
12 u - 73 = 7 u + 22
12 u - 7 u = 22 + 73
5 u = 95
1 u = 19
Number of stickers that Roshel had at first
= 7 u + 22
= 7 x 19 + 22
= 133 + 22
= 155
Answer(s): 155