Julie and Opal have some stickers. If Julie gives 19 stickers to Opal, Opal will have 4 times the number of stickers as Julie. If Opal gives 86 stickers to Julie, Julie will have
35 as many stickers as Opal. How many stickers does Julie have at first?
|
Case 1 |
Case 2 |
|
Julie |
Opal |
Julie |
Opal |
Before |
8 u + 19 |
32 u - 19 |
15 u - 86 |
25 u + 86 |
Change |
- 19 |
+ 19 |
+ 86 |
- 86 |
After |
1x8 = 8 u |
4x8 = 32 u |
3x5 = 15 u |
5x5 = 25 u |
The total number of stickers in both cases remains unchanged. Make the total number of stickers in both cases the same. LCM of 5 and 8 is 40.
Number of stickers that Julie had at first is the same in both cases.
15 u - 86 = 8 u + 19
15 u - 8 u = 19 + 86
7 u = 105
1 u = 15
Number of stickers that Julie had at first
= 8 u + 19
= 8 x 15 + 19
= 120 + 19
= 139
Answer(s): 139