Tiffany and Barbara have some coins. If Tiffany gives 11 coins to Barbara, Barbara will have 5 times the number of coins as Tiffany. If Barbara gives 44 coins to Tiffany, Tiffany will have
35 as many coins as Barbara. How many coins does Tiffany have at first?
|
Case 1 |
Case 2 |
|
Tiffany |
Barbara |
Tiffany |
Barbara |
Before |
4 u + 11 |
20 u - 11 |
9 u - 44 |
15 u + 44 |
Change |
- 11 |
+ 11 |
+ 44 |
- 44 |
After |
1x4 = 4 u |
5x4 = 20 u |
3x3 = 9 u |
5x3 = 15 u |
The total number of coins in both cases remains unchanged. Make the total number of coins in both cases the same. LCM of 6 and 8 is 24.
Number of coins that Tiffany had at first is the same in both cases.
9 u - 44 = 4 u + 11
9 u - 4 u = 11 + 44
5 u = 55
1 u = 11
Number of coins that Tiffany had at first
= 4 u + 11
= 4 x 11 + 11
= 44 + 11
= 55
Answer(s): 55