Nora and Pamela have some stamps. If Nora gives 19 stamps to Pamela, Pamela will have 5 times the number of stamps as Nora. If Pamela gives 41 stamps to Nora, Nora will have
35 as many stamps as Pamela. How many stamps does Nora have at first?
|
Case 1 |
Case 2 |
|
Nora |
Pamela |
Nora |
Pamela |
Before |
4 u + 19 |
20 u - 19 |
9 u - 41 |
15 u + 41 |
Change |
- 19 |
+ 19 |
+ 41 |
- 41 |
After |
1x4 = 4 u |
5x4 = 20 u |
3x3 = 9 u |
5x3 = 15 u |
The total number of stamps in both cases remains unchanged. Make the total number of stamps in both cases the same. LCM of 6 and 8 is 24.
Number of stamps that Nora had at first is the same in both cases.
9 u - 41 = 4 u + 19
9 u - 4 u = 19 + 41
5 u = 60
1 u = 12
Number of stamps that Nora had at first
= 4 u + 19
= 4 x 12 + 19
= 48 + 19
= 67
Answer(s): 67