Tammy and Tiffany have some beads. If Tammy gives 27 beads to Tiffany, Tiffany will have 4 times the number of beads as Tammy. If Tiffany gives 43 beads to Tammy, Tammy will have
35 as many beads as Tiffany. How many beads does Tammy have at first?
| |
Case 1 |
Case 2 |
| |
Tammy |
Tiffany |
Tammy |
Tiffany |
| Before |
8 u + 27 |
32 u - 27 |
15 u - 43 |
25 u + 43 |
| Change |
- 27 |
+ 27 |
+ 43 |
- 43 |
| After |
1x8 =
8 u |
4x8 =
32 u |
3x5 =
15 u |
5x5 =
25 u |
The total number of beads in both cases remains unchanged. Make the total number of beads in both cases the same. LCM of 5 and 8 is 40.
Number of beads that Tammy had at first is the same in both cases.
15 u - 43 = 8 u + 27
15 u - 8 u = 27 + 43
7 u = 70
1 u = 10
Number of beads that Tammy had at first
= 8 u + 27
= 8 x 10 + 27
= 80 + 27
= 107
Answer(s): 107
