Mary and Shiyun have some stickers. If Mary gives 15 stickers to Shiyun, Shiyun will have 4 times the number of stickers as Mary. If Shiyun gives 34 stickers to Mary, Mary will have
35 as many stickers as Shiyun. How many stickers does Mary have at first?
| |
Case 1 |
Case 2 |
| |
Mary |
Shiyun |
Mary |
Shiyun |
| Before |
8 u + 15 |
32 u - 15 |
15 u - 34 |
25 u + 34 |
| Change |
- 15 |
+ 15 |
+ 34 |
- 34 |
| After |
1x8 =
8 u |
4x8 =
32 u |
3x5 =
15 u |
5x5 =
25 u |
The total number of stickers in both cases remains unchanged. Make the total number of stickers in both cases the same. LCM of 5 and 8 is 40.
Number of stickers that Mary had at first is the same in both cases.
15 u - 34 = 8 u + 15
15 u - 8 u = 15 + 34
7 u = 49
1 u = 7
Number of stickers that Mary had at first
= 8 u + 15
= 8 x 7 + 15
= 56 + 15
= 71
Answer(s): 71
