Jen and Cathy have some stickers. If Jen gives 31 stickers to Cathy, Cathy will have 5 times the number of stickers as Jen. If Cathy gives 44 stickers to Jen, Jen will have
35 as many stickers as Cathy. How many stickers does Jen have at first?
|
Case 1 |
Case 2 |
|
Jen |
Cathy |
Jen |
Cathy |
Before |
4 u + 31 |
20 u - 31 |
9 u - 44 |
15 u + 44 |
Change |
- 31 |
+ 31 |
+ 44 |
- 44 |
After |
1x4 = 4 u |
5x4 = 20 u |
3x3 = 9 u |
5x3 = 15 u |
The total number of stickers in both cases remains unchanged. Make the total number of stickers in both cases the same. LCM of 6 and 8 is 24.
Number of stickers that Jen had at first is the same in both cases.
9 u - 44 = 4 u + 31
9 u - 4 u = 31 + 44
5 u = 75
1 u = 15
Number of stickers that Jen had at first
= 4 u + 31
= 4 x 15 + 31
= 60 + 31
= 91
Answer(s): 91